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Question
${{mg\,R\,\tan \,\theta } \over {{B^2}\,{l^2}}}$
${{mg\,R\,\cot \,\theta } \over {{B^2}\,{l^2}}}$
${{mg\,R\,\sin \,\theta } \over {{B^2}\,{l^2}}}$
${{mg\,R\,\cos \,\theta } \over {{B^2}\,{l^2}}}$

Solution

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