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Question
In a screw gauge, $5$ complete rotations of the screw cause it to move a linear distance of $0.25$ $cm.$ There are $100$ circular scale divisions. The thickness of a wire measured by this screw gauge gives a reading of $4$ main scale divisions and $30$ circular scale divisions. Assuming negligible zero error, the thickness of the wire is :
$0.4300$ $cm$
$0.2150$ $cm$
$0.3150$ $cm$
$0.0430$ $cm$

Solution

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