If $\,\,\,$ f$\left( {{{3x - 4} \over {3x + 4}}} \right)$ = x + 2, x $ \ne $ $-$ ${4 \over 3}$, and $\int {} $f(x) dx = A log$\left| {} \right.$1 $-$ x $\left| {} \right.$ + Bx + C, then the ordered pair (A, B) is equal to : (where C is a constant of integration)

Question

If $\,\,\,$ f$\left( {{{3x - 4} \over {3x + 4}}} \right)$ = x + 2, x $ \ne $ $-$ ${4 \over 3}$, and

$\int {} $f(x) dx = A log$\left| {} \right.$1 $-$ x $\left| {} \right.$ + Bx + C,

then the ordered pair (A, B) is equal to :

(where C is a constant of integration)

$\left( {{8 \over 3},{2 \over 3}} \right)$

$\left( { - {8 \over 3},{2 \over 3}} \right)$

$\left( { - {8 \over 3}, - {2 \over 3}} \right)$

$\left( { {8 \over 3}, - {2 \over 3}} \right)$

Solution

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