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Question
The electric field component of a monochromatic radiation is given by

$\overrightarrow E $ = 2 E0 $\widehat i$ cos kz cos $\omega $t

Its magnetic field $\overrightarrow B $ is then given by :
${{2{E_0}} \over c}$ $\widehat j$ sin kz cos $\omega $t
$-$ ${{2{E_0}} \over c}$ $\widehat j$ sin kz sin $\omega $t
${{2{E_0}} \over c}$ $\widehat j$ sin kz sin $\omega $t
${{2{E_0}} \over c}$ $\widehat j$ cos kz cos $\omega $t

Solution

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