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To solve the problem, we need to analyze the information given about the metal 'M' and the gas 'B' formed during the reactions.
### Step 1: Identify the Metal 'M'
The problem states that a metal 'M' reacts with nitrogen gas to form 'M3N'. This suggests that 'M' is likely a metal that can form a nitride. The options provided include:
- Li (Lithium)
- Ba (Barium)
- Na (Sodium)
- Al (Aluminum)
Among these, lithium (Li) is known to form lithium nitride ($Li_3N$) when it reacts with nitrogen gas. Therefore, we can conclude that 'M' is likely lithium.
### Step 2: Analyze the Reaction of 'M3N' with Heat
The problem mentions that 'M3N' upon heating gives back 'M'. This is consistent with the behavior of lithium nitride, which decomposes upon heating to yield lithium and nitrogen gas.
### Step 3: Identify the Gas 'B'
Next, we need to determine the gas 'B' produced when 'M' (lithium) reacts with water. The reaction of lithium with water produces lithium hydroxide and hydrogen gas:
$$
2Li + 2H_2O \rightarrow 2LiOH + H_2
$$
Thus, the gas 'B' is hydrogen ($H_2$).
### Step 4: Reaction of Gas 'B' with CuSO4
The problem states that gas 'B' reacts with an aqueous solution of CuSO4 to form a deep blue compound. When hydrogen gas is bubbled through a solution of copper(II) sulfate, it reduces the copper(II) ions to copper(I) ions, forming a deep blue complex known as cuprous hydroxide ($Cu_2O$) or cuprous sulfate.
### Conclusion
Based on the above analysis, we can conclude that:
- The metal 'M' is lithium (Li).
- The gas 'B' produced is hydrogen (H2).
Therefore, the correct answer is: 'M' and 'B' respectively are Li and H2.