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Question
The area (in sq. units) of the smaller portion enclosed between the curves, x2 + y2 = 4 and y2 = 3x, is :
${1 \over {2\sqrt 3 }} + {\pi \over 3}$
${1 \over {\sqrt 3 }} + {{2\pi } \over 3}$
${1 \over {2\sqrt 3 }} + {{2\pi } \over 3}$
${1 \over {\sqrt 3 }} + {{4\pi } \over 3}$

Solution

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