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Question
Magnetic field in a plane electromagnetic wave is given by

$\overrightarrow B $ = B0 sin (k x + $\omega $t) $\widehat j\,T$

Expression for corresponding electric field will be :
Where c is speed of light.
$\overrightarrow E $ = B0 c sin (k x + $\omega $t) $\widehat k$ V/m
$\overrightarrow E $ = ${{{B_0}} \over c}$ sin (k x + $\omega $t) $\widehat k$ V/m
$\overrightarrow E $ = $-$ B0 c sin (kx +$\omega $t) $\widehat k$ V/m
$\overrightarrow E $ = B0 c sin (kx $-$$\omega $t) $\widehat k$ V/m

Solution

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