© All Rights reserved @ LearnWithDash
To determine the identity of the organic acid 'X', we analyze the information provided in the question step by step.
### Step 1: Analyzing the Reaction with Concentrated H2SO4
The question states that the sodium salt of the organic acid 'X' produces effervescence when reacted with concentrated sulfuric acid ($\text{H}_2\text{SO}_4$). This effervescence indicates the release of a gas, which is typically carbon dioxide ($\text{CO}_2$) when a salt of a carboxylic acid reacts with a strong acid.
### Step 2: Identifying the Possible Organic Acids
The options provided are:
1. CH3COONa (Sodium acetate)
2. Na2C2O4 (Sodium oxalate)
3. C6H5COONa (Sodium benzoate)
4. HCOONa (Sodium formate)
Among these, sodium oxalate (Na2C2O4) is the only compound that can produce effervescence with concentrated sulfuric acid, as it can release carbon dioxide when it reacts.
### Step 3: Reaction with Acidified Aqueous CaCl2
Next, the question mentions that 'X' reacts with acidified aqueous calcium chloride ($\text{CaCl}_2$) to give a white precipitate. This is characteristic of calcium oxalate ($\text{CaC}_2\text{O}_4$), which is a white precipitate formed when oxalic acid reacts with calcium ions.
### Step 4: Decolorization of KMnO4
Finally, the organic acid 'X' is said to decolorize acidic KMnO4 solution. This indicates that 'X' is a reducing agent, which is true for oxalic acid as it can reduce permanganate ions ($\text{MnO}_4^-$) to manganese ions ($\text{Mn}^{2+}$), leading to the decolorization of the solution.
### Conclusion
Based on the above analysis, the organic acid 'X' is sodium oxalate (Na2C2O4), as it meets all the criteria outlined in the question.
