If for a positive integer n, the quadratic equation $x\left( {x + 1} \right) + \left( {x + 1} \right)\left( {x + 2} \right)$$ + .... + \left( {x + \overline {n - 1} } \right)\left( {x + n} \right)$$ = 10n$ has two consecutive integral solutions, then n is equal to :

Question

If for a positive integer n, the quadratic equation

$x\left( {x + 1} \right) + \left( {x + 1} \right)\left( {x + 2} \right)$$ + .... + \left( {x + \overline {n - 1} } \right)\left( {x + n} \right)$$ = 10n$

has two consecutive integral solutions, then n is equal to :

Solution

Please login to view the detailed solution steps...

Go to DASH