If x is a solution of the equation, $\sqrt {2x + 1} $ $ - \sqrt {2x - 1} = 1,$ $\,\,\left( {x \ge {1 \over 2}} \right),$ then $\sqrt {4{x^2} - 1} $ is equal to :
${3 \over 4}$
${1 \over 2}$
2
$2\sqrt 2 $
Solution
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