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Question
$\mathop {\lim }\limits_{x \to 0} \,{{{{\left( {1 - \cos 2x} \right)}^2}} \over {2x\,\tan x\, - x\tan 2x}}$ is :
$-$ 2
$-$ ${1 \over 2}$
${1 \over 2}$
2

Solution

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