The solution of the differential equation ${{dy} \over {dx}}\, + \,{y \over 2}\,\sec x = {{\tan x} \over {2y}},\,\,$ where 0 $ \le $ x < ${\pi \over 2}$, and y (0) = 1, is given by :

Question

The solution of the differential equation

${{dy} \over {dx}}\, + \,{y \over 2}\,\sec x = {{\tan x} \over {2y}},\,\,$

where 0 $ \le $ x < ${\pi \over 2}$, and y (0) = 1, is given by :

y = 1 $-$ ${x \over {\sec x + \tan x}}$

y² = 1 + ${x \over {\sec x + \tan x}}$

y² = 1 $-$ ${x \over {\sec x + \tan x}}$

y = 1 + ${x \over {\sec x + \tan x}}$

Solution

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