Let ABC be a triangle whose circumcentre is at P. If the position vectors of A, B, C and P are $\overrightarrow a ,\overrightarrow b ,\overrightarrow c $ and ${{\overrightarrow a + \overrightarrow b + \overrightarrow c } \over 4}$ respectively, then the position vector of the orthocentre of this triangle, is :

Question

${\overrightarrow a + \overrightarrow b + \overrightarrow c }$

$ - \left( {{{\overrightarrow a + \overrightarrow b + \overrightarrow c } \over 2}} \right)$

$\overrightarrow 0 $

$\left( {{{\overrightarrow a + \overrightarrow b + \overrightarrow c } \over 2}} \right)$

Solution

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