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Question
If   A > 0, B > 0   and    A + B = ${\pi \over 6}$,

then the minimum value of tanA + tanB is :
$\sqrt 3 - \sqrt 2 $
$2 - \sqrt 3 $
$4 - 2\sqrt 3 $
${2 \over {\sqrt 3 }}$

Solution

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