Identify the correct trend given below : (Atomic No.=Ti : 22, Cr : 24 and Mo : 42)
$\Delta $o of [Cr(H2O)6]2+ >
[Mo(H2O)6]2+ and
$\Delta $o of [Ti(H2O)6]3+ > [Ti(H2O)6]2+
$\Delta $o of [Cr(H2O)6]2+ >
[Mo(H2O)6]2+ and
$\Delta $o of [Ti(H2O)6]3+ < [Ti(H2O)6]2+
$\Delta $o of [Cr(H2O)6]2+
< [Mo(H2O)6]2+ and
$\Delta $o of [Ti(H2O)6]3+ > [Ti(H2O)6]2+
$\Delta $o of [Cr(H2O)6]2+
< [Mo(H2O)6]2+ and
$\Delta $o of [Ti(H2O)6]3+ < [Ti(H2O)6]2+
