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Question

The plot shows the variation of −$ln$ Kp versus temperature for the two reactions.

M(s) + ${1 \over 2}$ O2(g) $ \to $ MO(s) and

C(s) + ${1 \over 2}$ O2(g) $ \to $ CO(s)


Identify the correct statement :

At T > 1200 K, carbon will reduce MO(s) to M(s).
At T < 1200 K, the reaction

MO(s) + C(s) $ \to $ M(s) + CO(g) is spontaneous.
At T < 1200 K, oxidation of carbon is unfavourable
Oxidation of carbon is favourable at all temperatures.

Solution

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