The value of $\sum\limits_{r = 1}^{15} {{r^2}} \left( {{{{}^{15}{C_r}} \over {{}^{15}{C_{r - 1}}}}} \right)$ is equal to : - DASH

Your AI-Powered Personal Tutor

Question

The value of $\sum\limits_{r = 1}^{15} {{r^2}} \left( {{{{}^{15}{C_r}} \over {{}^{15}{C_{r - 1}}}}} \right)$ is equal to :

560

680

1240

1085

Solution

Please login to view the detailed solution steps...

Go to DASH