The shortest distance between the lines ${x \over 2} = {y \over 2} = {z \over 1}$ and ${{x + 2} \over { - 1}} = {{y - 4} \over 8} = {{z - 5} \over 4}$ lies in the interval :

Question

The shortest distance between the lines ${x \over 2} = {y \over 2} = {z \over 1}$ and
${{x + 2} \over { - 1}} = {{y - 4} \over 8} = {{z - 5} \over 4}$ lies in the interval :

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