In a triangle ABC, right angled at the vertex A, if the position vectors of A, B and C are respectively 3$\widehat i$ + $\widehat j$ $-$ $\widehat k$, $-$$\widehat i$ + 3$\widehat j$ + p$\widehat k$ and 5$\widehat i$ + q$\widehat j$ $-$ 4$\widehat k$, then the point (p, q) lies on a line :

Question

parallel to x-axis.

parallel to y-axis.

making an acute angle with the positive direction of x-axis.

making an obtuse angle with the positive direction of x-axis.

Solution

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