A wire of length $2$ units is cut into two parts which are bent respectively to form a square of side $=x$ units and a circle of radius $=r$ units. If the sum of the areas of the square and the circle so formed is minimum, then:
$x=2r$
$2x=r$
$2x = \left( {\pi + 4} \right)r$
$\left( {4 - \pi } \right)x = \pi \,\, r$
Solution
Please login to view the detailed solution steps...
