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Question
The area (in sq. units) of the region $\left\{ {\left( {x,y} \right):{y^2} \ge 2x\,\,\,and\,\,\,{x^2} + {y^2} \le 4x,x \ge 0,y \ge 0} \right\}$ is :
$\pi - {{4\sqrt 2 } \over 3}$
${\pi \over 2} - {{2\sqrt 2 } \over 3}$
$\pi - {4 \over 3}$
$\pi - {8 \over 3}$

Solution

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