Radiation of wavelength $\lambda ,$ is incident on a photocell. The fastest emitted electron has speed $v.$ If the wavelength is changed to ${{3\lambda } \over 4},$ the speed of the fastest emitted electron will be:

Question

$ = v{\left( {{4 \over 3}} \right)^{{1 \over 2}}}$

$ = v{\left( {{3 \over 4}} \right)^{{1 \over 2}}}$

$ > v{\left( {{4 \over 3}} \right)^{{1 \over 2}}}$

$ < v{\left( {{4 \over 3}} \right)^{{1 \over 2}}}$

Solution

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