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Question
The integral $\int {{{dx} \over {{x^2}{{\left( {{x^4} + 1} \right)}^{3/4}}}}} $ equals :
$ - {\left( {{x^4} + 1} \right)^{{1 \over 4}}} + c$
$ - {\left( {{{{x^4} + 1} \over {{x^4}}}} \right)^{{1 \over 4}}} + c$
$ {\left( {{{{x^4} + 1} \over {{x^4}}}} \right)^{{1 \over 4}}} + c$
$ {\left( {{x^4} + 1} \right)^{{1 \over 4}}} + c$

Solution

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