Let $y(x)$ be the solution of the differential equation $\left( {x\,\log x} \right){{dy} \over {dx}} + y = 2x\,\log x,\left( {x \ge 1} \right).$ Then $y(e)$ is equal to :

Question

Let $y(x)$ be the solution of the differential equation

$\left( {x\,\log x} \right){{dy} \over {dx}} + y = 2x\,\log x,\left( {x \ge 1} \right).$ Then $y(e)$ is equal to :