If $12$ different balls are to be placed in $3$ identical boxes, then the probability that one of the boxes contains exactly $3$ balls is :

Question

$220{\left( {{1 \over 3}} \right)^{12}}$

$22{\left( {{1 \over 3}} \right)^{11}}$

${{55} \over 3}{\left( {{2 \over 3}} \right)^{11}}$

$55{\left( {{2 \over 3}} \right)^{10}}$

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