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Question

An inductor $(L=0.03$ $H)$ and a resistor $\left( {R = 0.15\,k\Omega } \right)$ are connected in series to a battery of $15V$ $EMF$ in a circuit shown below. The key ${K_1}$ has been kept closed for a long time. Then at $t=0$, ${K_1}$ is opened and key ${K_2}$ is closed simultaneously. At $t=1$ $ms,$ the current in the circuit will be : $\left( {{e^5} \cong 150} \right)$

$6.7$ $mA$
$0.67$ $mA$
$100$ $mA$
$67$ $mA$

Solution

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