Question
Given below are the half-cell reactions:
Mn2+ + 2e- $\to$ Mn; Eo = -1.18 V
2(Mn3+ + e- $\to$ Mn2+); Eo = +1.51 V
The Eo for 3Mn2+ $\to$ Mn + 2Mn3+ will be :
Mn2+ + 2e- $\to$ Mn; Eo = -1.18 V
2(Mn3+ + e- $\to$ Mn2+); Eo = +1.51 V
The Eo for 3Mn2+ $\to$ Mn + 2Mn3+ will be :