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Question
If $x=-1$ and $x=2$ are extreme points of $f\left( x \right) = \alpha \,\log \left| x \right|+\beta {x^2} + x$ then
$\alpha = 2,\beta = - {1 \over 2}$
$\alpha = 2,\beta = {1 \over 2}$
$\alpha = - 6,\beta = {1 \over 2}$
$\alpha = - 6,\beta = -{1 \over 2}$

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