$\mathop {\lim }\limits_{x \to 0} {{\sin \left( {\pi {{\cos }^2}x} \right)} \over {{x^2}}}$ is equal to : - DASH

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Question

$\mathop {\lim }\limits_{x \to 0} {{\sin \left( {\pi {{\cos }^2}x} \right)} \over {{x^2}}}$ is equal to :

$ - \pi $

$ \pi $

${\pi \over 2}$

1

Solution

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