A parallel plate capacitor is made of two circular plates separated by a distance $5$ $mm$ and with a dielectric of dielectric constant $2.2$ between them. When the electric field in the dielectric is $3 \times {10^4}\,V/m$ the charge density of the positive plate will be close to:

Question

$6 \times {10^{ - 7}}\,\,C/{m^2}$

$3 \times {10^{ - 7}}\,\,C/{m^2}$

$3 \times {10^4}\,\,C/{m^2}$

$6 \times {10^4}\,\,C/{m^2}$

Solution

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