Statement-1 : The value of the integral $\int\limits_{\pi /6}^{\pi /3} {{{dx} \over {1 + \sqrt {\tan \,x} }}} $ is equal to $\pi /6$ Statement-2 : $\int\limits_a^b {f\left( x \right)} dx = \int\limits_a^b {f\left( {a + b - x} \right)} dx.$

Question

Statement-1 : The value of the integral
$\int\limits_{\pi /6}^{\pi /3} {{{dx} \over {1 + \sqrt {\tan \,x} }}} $ is equal to $\pi /6$

Statement-2 : $\int\limits_a^b {f\left( x \right)} dx = \int\limits_a^b {f\left( {a + b - x} \right)} dx.$

Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1.

Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1.

Statement- 1 is true; Statement-2 is False.

Statement-1 is false; Statement-2 is true.

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