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Question
If the lines ${{x - 2} \over 1} = {{y - 3} \over 1} = {{z - 4} \over { - k}}$ and ${{x - 1} \over k} = {{y - 4} \over 2} = {{z - 5} \over 1}$ are coplanar, then $k$ can have :
any value
exactly one value
exactly two values
exactly three values

Solution

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