Two capacitors ${C_1}$ and ${C_2}$ are charged to $120$ $V$ and $200$ $V$ respectively. It is found that connecting them together the potential on each one can be made zero. Then
$5{C_1} = 3{C_2}$
$3{C_1} = 5{C_2}$
$3{C_1} + 5{C_2} = 0$
$9{C_1} = 4{C_2}$
Solution
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