If $g\left( x \right) = \int\limits_0^x {\cos 4t\,dt,} $ then $g\left( {x + \pi } \right)$ equals

Question

${{g\left( x \right)} \over {8\left( \pi \right)}}$

$g\left( x \right) + g\left( \pi \right)$

$g\left( x \right) - g\left( \pi \right)$

$g\left( x \right) . g\left( \pi \right)$

Please login to view the detailed solution steps...