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Question

A wooden wheel of radius $R$ is made of two semicircular part (see figure). The two parts are held together by a ring made of a metal strip of cross sectional area $S$ and length $L.$ $L$ is slightly less than $2\pi R.$ To fit the ring on the wheel, it is heated so that its temperature rises by $\Delta T$ and it just steps over the wheel. As it cools down to surrounding temperature, it process the semicircular parts together. If the coefficient of linear expansion of the metal is $\alpha $, and its Young's modulus is $Y,$ the force that one part of the wheel applies on the other part is :

$2\pi SY\alpha \Delta T$
$SY\alpha \Delta T$
$\pi SY\alpha \Delta T$
$2SY\alpha \Delta T$

Solution

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