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Question
A diatomic molecule is made of two masses ${m_1}$ and ${m_2}$ which are separated by a distance $r.$ If we calculate its rotational energy by applying Bohr's rule of angular momentum quantization, its energy will be given by: ($n$ is an integer)
${{{{\left( {{m_1} + {m_2}} \right)}^2}{n^2}{h^2}} \over {2m_1^2m_2^2{r^2}}}$
${{{n^2}{h^2}} \over {2\left( {{m_1} + {m_2}} \right){r^2}}}$
${{2{n^2}{h^2}} \over {\left( {{m_1} + {m_2}} \right){r^2}}}$
${{\left( {{m_1} + {m_2}} \right){n^2}{h^2}} \over {2{m_1}{m_2}{r^2}}}$

Solution

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