The given circuit is equivalent to: - DASH

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The given circuit is equivalent to:

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Step-by-Step Solution Step 1: Observe the Given Expression The given circuit can be analyzed to yield the output expression: $Y = \overline{\overline{A} + \overline{B}}$ This comes from applying the logic diagram conversion into an equivalent Boolean expression. Step 2: Apply De Morgan's Theorem De Morgan's theorem states: $ \overline{P + Q} = \overline{P}\,\cdot\,\overline{Q} $ Using this on $ \overline{\overline{A} + \overline{B}} $ gives: $ Y = \overline{\overline{A}} \,\cdot\, \overline{\overline{B}} $ Step 3: Simplify Double Negations Notice that $ \overline{\overline{A}} = A $ and $ \overline{\overline{B}} = B $. Hence: $ Y = A \cdot B $ Step 4: Recognize the Logic Gate The expression $ A \cdot B $ represents the output of an AND gate. Therefore, the given circuit is equivalent to an AND gate. Step 5: Final Representation The correct answer corresponds to the AND gate with the Boolean expression $ Y = A \cdot B $. Reference Image for the AND Gate

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