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Question

If a conducting sphere of radius $\mathrm{R}$ is charged. Then the electric field at a distance $\mathrm{r}(\mathrm{r} > \mathrm{R})$ from the centre of the sphere would be, $(\mathrm{V}=$ potential on the surface of the sphere)

$\frac{r V}{R^2}$
$\frac{R^2 V}{r^3}$
$\frac{R V}{r^2}$
$\frac{\mathrm{V}}{\mathrm{r}}$

Solution

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