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Question

A container of volume $200 \mathrm{~cm}^3$ contains 0.2 mole of hydrogen gas and 0.3 mole of argon gas. The pressure of the system at temperature $200 \mathrm{~K}$ ($\mathrm{R}=8.3 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}$) will be :-

$6.15 \times 10^5 \mathrm{~Pa}$
$6.15 \times 10^4 \mathrm{~Pa}$
$4.15 \times 10^5 \mathrm{~Pa}$
$4.15 \times 10^6 \mathrm{~Pa}$

Solution

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