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Question

To produce an instantaneous displacement current of $2 \mathrm{~mA}$ in the space between the parallel plates of a capacitor of capacitance $4 ~\mu \mathrm{F}$, the rate of change of applied variable potential difference $\left(\frac{\mathrm{dV}}{\mathrm{dt}}\right)$ must be :-

$800 \mathrm{~V} / \mathrm{s}$
$500 \mathrm{~V} / \mathrm{s}$
$200 \mathrm{~V} / \mathrm{s}$
$400 \mathrm{~V} / \mathrm{s}$

Solution

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