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Question
A solution containing 2.675g of CoCl3. 6NH3 (molar mass = 267.5 g mol–1) is passed through a cation exchanger. The chloride ions obtained in solution were treated with excess of AgNO3 to give 4.78 g of AgCl (molar mass = 143.5 g mol–1). The formula of the complex is : (At. Mass of Ag = 108 u)
[Co(NH3)6]Cl3
[CoCl2(NH3)4]Cl
[CoCl3(NH3)3]
[CoCl(NH3)5]Cl2

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