The area bounded by the curves $y = \cos x$ and $y = \sin x$ between the ordinates $x=0$ and $x = {{3\pi } \over 2}$ is - DASH

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Question

The area bounded by the curves $y = \cos x$ and $y = \sin x$ between the ordinates $x=0$ and $x = {{3\pi } \over 2}$ is

$4\sqrt 2 + 2$

$4\sqrt 2 - 1$

$4\sqrt 2 + 1$

$4\sqrt 2 - 2$

Solution

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