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Question

The conductivity of centimolar solution of $\mathrm{KCl}$ at $25^{\circ} \mathrm{C}$ is $0.0210 ~\mathrm{ohm}^{-1} \mathrm{~cm}^{-1}$ and the resistance of the cell containing the solution at $25^{\circ} \mathrm{C}$ is $60 ~\mathrm{ohm}$. The value of cell constant is -

$3.28 \mathrm{~cm}^{-1}$
$1.26 \mathrm{~cm}^{-1}$
$3.34 \mathrm{~cm}^{-1}$
$1.34 \mathrm{~cm}^{-1}$

Solution

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