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Question

The correct order of energies of molecular orbitals of $\mathrm{N}_{2}$ molecule, is

$\sigma 1 \mathrm{~s} < \sigma^{*} 1 \mathrm{~s} < \sigma 2 \mathrm{~s} < \sigma^{*} 2 \mathrm{~s} < \sigma 2 \mathrm{p}_{\mathrm{z}} < \left(\pi 2 \mathrm{p}_{\mathrm{x}}=\pi 2 \mathrm{p}_{\mathrm{y}}\right) < \left(\pi^{*} 2 \mathrm{p}_{\mathrm{x}}=\pi^{*} 2 \mathrm{p}_{\mathrm{y}}\right) < \sigma^{*} 2 \mathrm{p}_{\mathrm{z}}$
$\sigma 1 \mathrm{~s} <\sigma^{*} 1 \mathrm{~s} <\sigma 2 \mathrm{~s} < \sigma^{*} 2 \mathrm{~s} < \sigma 2 \mathrm{p}_{\mathrm{z}} < \sigma^{*} 2 \mathrm{p}_{\mathrm{z}} < \left(\pi 2 \mathrm{p}_{\mathrm{x}}=\pi 2 \mathrm{p}_{\mathrm{y}}\right) < \left(\pi^{*} 2 \mathrm{p}_{\mathrm{x}}=\pi^{*} 2 \mathrm{p}_{\mathrm{y}}\right)$
$\sigma 1 \mathrm{~s} <\sigma^{*} 1 \mathrm{~s} <\sigma 2 \mathrm{~s} < \sigma^{*} 2 \mathrm{~s} < \left(\pi 2 \mathrm{p}_{\mathrm{x}}=\pi 2 \mathrm{p}_{\mathrm{y}}\right) < \left(\pi^{*} 2 \mathrm{p}_{\mathrm{x}}=\pi^{*} 2 \mathrm{p}_{\mathrm{y}}\right) < \sigma 2 \mathrm{p}_{\mathrm{z}} < \sigma^{*} 2 \mathrm{p}_{\mathrm{z}}$
$\sigma 1 \mathrm{~s} <\sigma^{*} 1 \mathrm{~s} <\sigma 2 \mathrm{~s} < \sigma^{*} 2 \mathrm{~s} < \left(\pi 2 \mathrm{p}_{\mathrm{x}}=\pi 2 \mathrm{p}_{\mathrm{y}}\right) < \sigma 2 \mathrm{p}_{\mathrm{z}} < \left(\pi^{*} 2 \mathrm{p}_{\mathrm{x}}=\pi^{*} 2 \mathrm{p}_{\mathrm{y}}\right) < \sigma^{*} 2 \mathrm{p}_{\mathrm{z}}$

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