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Question

The right option for the mass of $\mathrm{CO}_{2}$ produced by heating $20 \mathrm{~g}$ of $20 \%$ pure limestone is

(Atomic mass of $\mathrm{Ca}=40$ )

$\left[\mathrm{CaCO}_{3} \stackrel{1200 \mathrm{~K}}{\longrightarrow} \mathrm{CaO}+\mathrm{CO}_{2}\right]$

1.76 g
2.64 g
1.32 g
1.12 g

Solution

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