In Cannizzaro reaction given below 2PhCHO $$\buildrel {\mathop {:OH}\limits^{\left( - \right)} } \over \longrightarrow $ PhCH2OH + $PhC\mathop O\limits^{..} $$2(-) the slowest step is :

Question

In Cannizzaro reaction given below
2PhCHO $$\buildrel {\mathop {:OH}\limits^{\left( - \right)} } \over \longrightarrow $ PhCH₂OH + $PhC\mathop O\limits^{..} $$₂^(-)
the slowest step is :

the transfer of hydride to the carbonyl group

the abstraction of proton from the carboxylic group

the attack of $:\mathop {OH}\limits^{( - )} $ at the carboxyl group

the deprotonation of Ph CH₂OH

Solution

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