The lines $p\left( {{p^2} + 1} \right)x - y + q = 0$ and $\left( {{p^2} + 1} \right){}^2x + \left( {{p^2} + 1} \right)y + 2q$ $=0$ are perpendicular to a common line for :
exactly one values of $p$
exactly two values of $p$
more than two values of $p$
no value of $p$
Solution
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