The ellipse ${x^2} + 4{y^2} = 4$ is inscribed in a rectangle aligned with the coordinate axex, which in turn is inscribed in another ellipse that passes through the point $(4,0)$. Then the equation of the ellipse is :
${x^2} + 12{y^2} = 16$
$4{x^2} + 48{y^2} = 48$
$4{x^2} + 64{y^2} = 48$
${x^2} + 16{y^2} = 16$
Solution
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