Let $f\left( x \right) = {\left( {x + 1} \right)^2} - 1,x \ge - 1$ Statement - 1 : The set $\left\{ {x:f\left( x \right) = {f^{ - 1}}\left( x \right)} \right\} = \left\{ {0, - 1} \right\}$. Statement - 2 : $f$ is a bijection.

Question

Let $f\left( x \right) = {\left( {x + 1} \right)^2} - 1,x \ge - 1$

Statement - 1 : The set $\left\{ {x:f\left( x \right) = {f^{ - 1}}\left( x \right)} \right\} = \left\{ {0, - 1} \right\}$.

Statement - 2 : $f$ is a bijection.

Statement - 1 is true, Statement - 2 is true; Statement - 2 is a correct explanation for Statement - 1

Statement - 1 is true, Statement - 2 is true; Statement - 2 is not a correct explanation for Statement - 1

Statement - 1 is true, Statement - 2 is false

Statement - 1 is false, Statement - 2 is true

Solution

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