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Question

In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of $2.0 \times 10^{10} \mathrm{~Hz}$ and amplitude $48 ~\mathrm{Vm}^{-1}$. Then the amplitude of oscillating magnetic field is : (Speed of light in free space $=3 \times 10^{8} \mathrm{~m} \mathrm{~s}^{-1}$ )

$1.6 \times 10^{-8} \mathrm{~T}$
$1.6 \times 10^{-7} \mathrm{~T}$
$1.6 \times 10^{-6} \mathrm{~T}$
$1.6 \times 10^{-9} \mathrm{~T}$

Solution

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